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How to Deserialize JSON Data into a C# Class Without a Default Constructor?

Linda Hamilton
Linda HamiltonOriginal
2025-01-29 16:32:10858browse

How to Deserialize JSON Data into a C# Class Without a Default Constructor?

json.net: No need to default to construct the function of the function of the function

The default constructor of JSON.NET can seamlessly sequence the JSON data into the object. However, if your class needs to be reinstated, the default constructor may hinder the processing process. This problem occurs when JSON data is consistent with the parameters of the heavy load constructor but there is a default constructor.

Solution: Cover the default behavior

In order to prevent json.net from using the default constructor, there are two ways:

<.> 1. Use [JSONCONSTRUCTOR] Features:

JSON.NET allows you to specify the preferred retrofitable constructor with the [JSONCONSTRUCTOR] feature. By using the constructor required for this feature, you can force JSON.NET to use it, even if the default constructor is defined. Keep in mind that the constructor parameter should be consistent with the JSON object attribute (ignore the lowercase). <.> 2. Create a custom JSONCONVERTER:

or, if you cannot modify the class, you can create a custom JSONCONVERRER to control the processing process. The readjson method of the converter can be customized in order to use the non -default constructor constructing object and fill any other attributes according to JSON data.

Example:

Considering the following classes with constructive functions:

To use the [JSONCONSTRUCTOR] feature method, please use the preferred constructor of this feature decoration, as shown below:

On the other hand, for custom JSONCONVERRER method, you can define the converter shown below:

<code class="language-csharp">public class Result
{
    public Result() { }

    [JsonConstructor]
    public Result(int? code, string format, Dictionary<string, string> details = null)
    {
        Code = code ?? ERROR_CODE;
        Format = format;

        if (details == null)
            Details = new Dictionary<string, string>();
        else
            Details = details;
    }
}</code>

In the readjson method of this converter, you can use the non -default constructor to instantiate the result object and fill any other attributes according to JSON data.

<code class="language-csharp">[JsonConstructor]
public Result(int? code, string format, Dictionary<string, string> details = null)
{
    ...
}</code>
By using these technologies, you can cover the default behavior of json.net and enable the derivative of the use of the heavy load constructor, even if there is a default constructor function.

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