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What's the Most Efficient Way to Read a Text File Line by Line in C#?

Linda Hamilton
Linda HamiltonOriginal
2025-01-29 08:25:10353browse

What's the Most Efficient Way to Read a Text File Line by Line in C#?

C#efficiently read text files

When handling text files in C#, it is important to read it efficiently. The commonly used method is to use to parse files by line. However, in order to improve performance, there are several other technologies worth considering.

<.> 1. StreamReader with the buffer: StreamReader.ReadLine()

The default buffer size is 1024 bytes. Increasing this value can significantly improve performance, especially for large files. Consider using the following code setting buffer size:

<.> 2. File.readlines:

StreamReader

This method provides more efficient alternatives than
<code class="language-csharp">using (var fileStream = File.OpenRead(fileName))
using (var streamReader = new StreamReader(fileStream, Encoding.UTF8, true, 128))
{
    string line;
    while ((line = streamReader.ReadLine()) != null)
    {
        // 处理每一行
    }
}</code>
. It is loaded on demand to minimize memory consumption:

<.> 3. File.readalllines:

StreamReader.ReadLine() This method returns all the array of all rows, but compared with

, the memory efficiency is low. If you need to access the row randomly, this method is applicable:
<code class="language-csharp">var lines = File.ReadLines(fileName);
foreach (var line in lines)
    // 处理每一行</code>

<.> 4. String.split:

The use of The most efficiency of the division line, especially for large documents. It needs to load the entire file into the memory and allocate a array for all rows: File.ReadLines

<code class="language-csharp">var lines = File.ReadAllLines(fileName);
for (var i = 0; i < lines.Length; i++)
    // 处理每一行</code>
Recommended method:

In order to obtain the best performance, it is recommended to use

because it has a balance between speed and memory efficiency. If you need a specific file sharing option, you can consider using the

with the size of the buffer. String.Split

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