Why Does byte byte = int in C# Arithmetic Operations?

C#arithmetic operation: Why byte byte = int?

Cise type conversion and arithmetic operation: Byte byte = int

In C#, the mathematical computing results involving Byte or Short types will be automatically converted into int type. This behavior may lead to unexpected results when processing small numbers stored in the Byte array. At first, people may think that operations like Byte Byte and Short Short will return the value of the same type as the number of operations, and obtain the Byte and Short values, respectively. However, this is not the case in C#.

The reason behind this behavior is the internal representation of the number type in the CLR (when the public language is running). All numerical operations are performed using 32 -bit integer, regardless of the type of operation. Therefore, when two byte are added, they are first converted into an integer, and the result is also an integer.

This hidden type conversion ensures the accuracy of the results. For example, if the values ​​of the two Byte variables are 1 and 2, they will be 3. If the result is converted back to Byte, it will be cut to 0 because the value exceeds the valid range of Byte (0-255).

As shown in , the result can be converted back to BYTE by explicitly converting the result to smaller data types, and may be introduced or overflowing errors. This explicit conversion requires additional code to reduce the readability of the operation, and it may be introduced to the BUG.

In your case, using the Byte array to store small numbers can improve performance because the cache hit rate is higher. However, the required explicit conversion will reduce readability. To solve this problem, you can consider using a special Ulong array, which can store 64 -bit non -symbolic integers. Although the Ulong operation also generates the ULONG value, they provide a larger range (0-18,446,744,073,709,551,615) and can eliminate the needs of explicit conversion.

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