How Can I Get a Double Result from Integer Division in C#?

Get the dual accuracy of the C#integer removal method

C#integer removal of the decimal part, only the integer result is returned. But sometimes we need to get dual -precision floating -point results.

To achieve this, the number of operations can be converted into

type before the division operation. For example:

double

Here, and

<code class="language-csharp">double num3 = (double)num1 / (double)num2;</code>

are integer, but convert it to

and then perform dividends. The result will be the num1 type. This is because the integer is converted to num2 to store the value of the integer into a floating point number. double double It should be noted that if any operation in C#is double type, the floating point removal method will be performed, and the result is also

type. Therefore, the following code can also work normally:

double double For more information about floating -point operations and type conversion in C#, please refer to dot net perls:

<code class="language-csharp">double num3 = (double)num1 / num2;</code>

Dot NET PERLS: Type conversion

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