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Convert complex SQL queries containing multiple joins, counts and left joins to LINQ
This example demonstrates how to convert a complex SQL query containing multiple joins and aggregations into an equivalent LINQ query. This query retrieves data from three tables (TABLE_C, TABLE_V, and TABLE_R) and performs a distinct count operation on specific columns.
Convert SQL to LINQ query understanding:
into
and DefaultIfEmpty()
to simulate a LEFT JOIN. Distinct()
to count aggregated results. The following is LINQ code written in query expression syntax:
<code class="language-csharp">var subrq = from r in Table_R group r by r.Id into rg select new { Id = rg.Key, cnt = rg.Count() }; var ansq = (from c in Table_C join v in Table_V on c.Id equals v.Id join r in subrq on c.Id equals r.Id into rj from r in rj.DefaultIfEmpty() where c.IdUser == "1234" group new { c, v, r } by new { c.Id, c.Title, r.cnt } into cvrg select new { cvrg.Key.Title, Nb_V2 = cvrg.Count(), Nb_V1 = cvrg.Select(cvr => cvr.v.IdUser).Distinct().Count(), Nb_R = (int?)cvrg.Key.cnt }).Distinct();</code>
The following is the equivalent LINQ code written in Lambda expression syntax:
<code class="language-csharp">var subr2 = Table_R.GroupBy(r => r.Id).Select(rg => new { Id = rg.Key, cnt = rg.Count() }); var ans2 = Table_C.Where(c => c.IdUser == "1234") .Join(Table_V, c => c.Id, v => v.Id, (c, v) => new { c, v }) .GroupJoin(subr2, cv => cv.c.Id, r => r.Id, (cv, rj) => new { cv.c, cv.v, rj }) .SelectMany(cvrj => cvrj.rj.DefaultIfEmpty(), (cvrj, r) => new { cvrj.c, cvrj.v, r }) .GroupBy(cvr => new { cvr.c.Id, cvr.c.Title, cvr.r?.cnt }) //处理r可能为null的情况 .Select(cvrg => new { cvrg.Key.Title, Nb_V2 = cvrg.Count(), Nb_V1 = cvrg.Select(cvr => cvr.v.IdUser).Distinct().Count(), Nb_R = (int?)cvrg.Key.cnt }).Distinct();</code>
Pay attention to the processing of cvr.r.cnt
in the Lambda expression version. The ?.
null conditional operator is added to handle the situation where r
may be null, avoiding NullReferenceException exceptions. Both methods accomplish the same functionality, and which method you choose comes down to personal preference.
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