Enforcing Uniqueness Across Multiple SQL Server Columns
Often, database integrity requires preventing duplicate rows based on multiple column values. This article demonstrates how to enforce a unique constraint across the PersonNumber
and Active
columns in a Person
table.
Implementing the Unique Constraint
After removing any pre-existing duplicate entries, apply the constraint using one of these methods:
-
ALTER TABLE
Statement: This directly adds the constraint to the existing table.ALTER TABLE dbo.Person ADD CONSTRAINT uq_Person_NumberActive UNIQUE (PersonNumber, Active);
-
CREATE UNIQUE INDEX
Statement: This creates a unique index, which implicitly enforces the uniqueness constraint.CREATE UNIQUE INDEX uq_Person_NumberActive ON dbo.Person (PersonNumber, Active);
Alternative Approaches & Optimization
While the above methods are effective, consider these enhancements:
-
Performance: Proactive duplicate checks before attempting an insert can improve performance by avoiding exceptions within
TRY...CATCH
blocks. -
INSTEAD OF
Trigger: AnINSTEAD OF
trigger allows for conditional insert logic, preventing exceptions from propagating to the application layer. This offers a more robust error-handling mechanism.
Illustrative Example
This example demonstrates the unique constraint in action:
-- Create the Person table CREATE TABLE dbo.Person ( ID INT IDENTITY(1, 1) PRIMARY KEY, Name NVARCHAR(32) NOT NULL, Active BIT NOT NULL DEFAULT 0, PersonNumber INT NOT NULL ); -- Add the unique constraint ALTER TABLE dbo.Person ADD CONSTRAINT uq_Person_NumberActive UNIQUE (PersonNumber, Active); -- Insert data INSERT INTO dbo.Person (Name, Active, PersonNumber) VALUES ('John Doe', 1, 1234); INSERT INTO dbo.Person (Name, Active, PersonNumber) VALUES ('Jane Doe', 0, 5678); -- Attempt to insert a duplicate (this will fail) INSERT INTO dbo.Person (Name, Active, PersonNumber) VALUES ('John Doe', 1, 1234);
This ensures that only one record exists for each unique combination of PersonNumber
and Active
status. Any attempt to insert a duplicate will result in an error. Remember to replace dbo.Person
with your actual schema and table name.
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