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How to Serialize and Deserialize Objects in C#?

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2025-01-23 11:42:11237browse

How to Serialize and Deserialize Objects in C#?

Saving and restoring C# objects: serialization and deserialization

Serialization stores data in a portable format, making it easier to transfer objects between different applications, systems, or machines.

To serialize an object, you must use the [Serializable] attribute tag and include a parameterless constructor. Additionally, the [XmlIgnore] and [JsonIgnore] attributes can be used to exclude specific attributes or fields.

Example

Consider the following SomeClass:

<code class="language-csharp">[Serializable]
public class SomeClass
{
    public string someProperty { get; set; }
}

SomeClass object1 = new SomeClass { someProperty = "someString" };</code>

Save to file

  • BinarySerialization:

    <code class="language-csharp">  BinaryFormatter binaryFormatter = new BinaryFormatter();
    
      using (Stream stream = File.Create("object1.bin"))
      {
          binaryFormatter.Serialize(stream, object1);
      }</code>
  • XML Serialization:

    <code class="language-csharp">  XmlSerializer serializer = new XmlSerializer(typeof(SomeClass));
    
      using (TextWriter writer = new StreamWriter("object1.xml"))
      {
          serializer.Serialize(writer, object1);
      }</code>
  • JSONSerialization:

    <code class="language-csharp">  using (StreamWriter writer = new StreamWriter("object1.json"))
      {
          writer.Write(JsonConvert.SerializeObject(object1));
      }</code>

Recover from Files

  • BinaryDeserialization:

    <code class="language-csharp">  BinaryFormatter binaryFormatter = new BinaryFormatter();
    
      using (Stream stream = File.OpenRead("object1.bin"))
      {
          object1 = (SomeClass)binaryFormatter.Deserialize(stream);
      }</code>
  • XML Deserialization:

    <code class="language-csharp">  XmlSerializer serializer = new XmlSerializer(typeof(SomeClass));
    
      using (TextReader reader = new StreamReader("object1.xml"))
      {
          object1 = (SomeClass)serializer.Deserialize(reader);
      }</code>
  • JSON Deserialization (JsonDeserialization):

    <code class="language-csharp">  using (StreamReader reader = new StreamReader("object1.json"))
      {
          object1 = JsonConvert.DeserializeObject<SomeClass>(reader.ReadToEnd());
      }</code>

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