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HomeBackend DevelopmentC++How to Automatically Validate an XML File Against its Referenced XSD in C#?

How to Automatically Validate an XML File Against its Referenced XSD in C#?

Validate XML against referenced XSD in C#

Question:

How to automatically validate an XML file containing a specified schema location in C# without explicitly specifying the schema to validate, like Visual Studio does when opening the file?

Answer:

To automatically validate an XML file against a referenced XSD in C#, without explicitly specifying the schema, you need to create an instance of XmlReaderSettings and pass it to it when creating the XmlReader. Validation errors can be received by subscribing to settings in ValidationEventHandler.

Here is a sample code demonstrating this method:

using System.Xml;
using System.Xml.Schema;
using System.IO;

public class XML验证
{
    public static void Main()
    {
        // 设置验证设置。
        XmlReaderSettings settings = new XmlReaderSettings();
        settings.ValidationType = ValidationType.Schema;
        settings.ValidationFlags |= XmlSchemaValidationFlags.ProcessInlineSchema;
        settings.ValidationFlags |= XmlSchemaValidationFlags.ProcessSchemaLocation;
        settings.ValidationFlags |= XmlSchemaValidationFlags.ReportValidationWarnings;
        settings.ValidationEventHandler += new ValidationEventHandler(ValidationCallBack);

        // 创建XmlReader对象。
        XmlReader reader = XmlReader.Create("inlineSchema.xml", settings);

        // 解析文件。
        while (reader.Read()) ;

    }
    // 显示任何警告或错误。
    private static void ValidationCallBack(object sender, ValidationEventArgs args)
    {
        if (args.Severity == XmlSeverityType.Warning)
            Console.WriteLine("\t警告:未找到匹配的模式。未进行验证。" + args.Message);
        else
            Console.WriteLine("\t验证错误: " + args.Message);

    }
}

Using this method, validation will be performed automatically based on the pattern specified in the XML file's xsi:schemaLocation attribute.

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