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SQL Server JOINs and CASE Statements: A Common Pitfall
In SQL Server 2008 R2 (and later versions), attempting to use a CASE
statement directly within a JOIN
condition to define the join criteria can lead to syntax errors. Let's examine why and how to solve this.
Consider the relationship between sys.partitions
and sys.allocation_units
, where the join depends on the sys.allocation_units.type
value. A naive approach might look like this:
<code class="language-sql">SELECT * FROM sys.indexes i JOIN sys.partitions p ON i.index_id = p.index_id JOIN sys.allocation_units a ON CASE WHEN a.type IN (1, 3) THEN a.container_id = p.hobt_id WHEN a.type IN (2) THEN a.container_id = p.partition_id END</code>
This results in the error "Incorrect syntax near '='". The problem is that the CASE
expression itself doesn't produce a Boolean (TRUE/FALSE) result suitable for a join condition. Instead, it returns either a.container_id = p.hobt_id
or a.container_id = p.partition_id
, neither of which is a valid join condition on its own.
The Correct Approach: Boolean Evaluation
To fix this, we need the CASE
expression to yield a Boolean value. We can achieve this by structuring the CASE
statement to return 1 for true and 0 for false, and then comparing the result to 1:
<code class="language-sql">SELECT * FROM sys.indexes i JOIN sys.partitions p ON i.index_id = p.index_id JOIN sys.allocation_units a ON CASE WHEN a.type IN (1, 3) AND a.container_id = p.hobt_id THEN 1 WHEN a.type IN (2) AND a.container_id = p.partition_id THEN 1 ELSE 0 END = 1</code>
Now, the CASE
statement evaluates to 1 only when the appropriate conditions (based on a.type
) and the equality check (a.container_id = p.hobt_id
or a.container_id = p.partition_id
) are both true. The = 1
comparison then provides the necessary Boolean result for the JOIN
condition. This revised query correctly joins the tables. This method ensures that the JOIN
condition evaluates to a true or false value, enabling the join to function as intended.
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