


Tackling JSON.NET Interface Deserialization with Constructor Parameters
Deserializing JSON data containing interface properties presents a common hurdle in JSON.NET. This challenge, however, is readily addressed by leveraging constructor parameters to define specific class implementations.
JSON.NET's deserialization process cleverly identifies and maps concrete classes to interface properties based on the constructors supplied. Let's illustrate this with an example:
public class Visit : IVisit { public Visit(MyLocation location, Guest guest) { Location = location; Guest = guest; } public long VisitId { get; set; } public ILocation Location { get; set; } public DateTime VisitDate { get; set; } public IGuest Guest { get; set; } }
Here, the Visit
constructor explicitly accepts MyLocation
and Guest
objects. This crucial step guides JSON.NET to correctly deserialize the Location
and Guest
interface properties using these specified concrete types.
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