How to Deserialize XML into Objects using XmlSerializer in C#?

Use C# XmlSerializer to deserialize XML into objects

This article introduces how to use C#'s XmlSerializer class to deserialize XML data into objects. This requires you to define a C# class that matches the XML structure. The steps are as follows:

1. Create matching class structure:

First, create a class corresponding to the XML root element. For example, if the root element of XML is <StepList>, create a class named StepList:

<code class="language-csharp">[XmlRoot("StepList")]
public class StepList
{
    // ...
}</code>

2. Add attributes:

Next, add the corresponding attributes to the class for each child element in the XML. Use the XmlElement attribute to specify element names. For example:

<code class="language-csharp">public class Step
{
    [XmlElement("Name")]
    public string Name { get; set; }

    [XmlElement("Desc")]
    public string Desc { get; set; }
}</code>

3. Deserialize using XmlSerializer:

Finally, use XmlSerializer to deserialize the XML into an object:

<code class="language-csharp">XmlSerializer serializer = new XmlSerializer(typeof(StepList));
using (TextReader reader = new StringReader(xmlString)) // xmlString 为您的XML字符串
{
    StepList result = (StepList)serializer.Deserialize(reader);
}</code>

Based on the XML example provided, a suitable class structure is as follows:

<code class="language-csharp">[XmlRoot("StepList")]
public class StepList
{
    [XmlElement("Step")]
    public List<Step> Steps { get; set; }
}

public class Step
{
    [XmlElement("Name")]
    public string Name { get; set; }

    [XmlElement("Desc")]
    public string Desc { get; set; }
}</code>

Through the above steps, you can easily map XML data to C# objects to facilitate subsequent processing and use.

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