Extract specific columns from a PostgreSQL table as an array of JSON objects
Question:
You have a table with multiple columns and want to return an array of objects for each row, with two columns grouped according to another column. However, you'll run into the problem that the result contains an extra key in each object. The desired output is an array of objects with only two columns, grouped by a third column.
PostgreSQL 10 solution:
For PostgreSQL 10 and above, you can use the -
operator to remove a single key (or array of keys in PostgreSQL 10) from a jsonb
object before aggregating.
SELECT val2, jsonb_agg(to_jsonb(t.*) - '{id, val2}'::text[]) AS js_34 FROM tbl t GROUP BY val2;
PostgreSQL 9.4 solution:
In PostgreSQL 9.4 and above, you can use jsonb_build_object()
or json_build_object()
to create a JSON object from alternating keys and values.
SELECT val2, jsonb_agg(jsonb_build_object('val3', val3, 'val4', val4)) AS js_34 FROM tbl GROUP BY val2;
PostgreSQL 9.3 solution:
For PostgreSQL 9.3 and above, you can use to_jsonb()
and ROW expressions to create JSON objects. You can also use subqueries instead of ROW expressions.
SELECT val2, jsonb_agg(to_jsonb((val3, val4))) AS js_34 FROM tbl GROUP BY val2; SELECT val2, jsonb_agg(to_jsonb((SELECT t FROM (SELECT val3, val4) t))) AS js_34 FROM tbl GROUP BY val2;
The above solution will return the desired result: an array of objects with only two columns, grouped by the third column.
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