


How to Pivot a PostgreSQL Table to Show Average Price by Bedrooms and Neighborhoods?
Creating a pivot table in PostgreSQL
PostgreSQL uses the crosstab()
function to create pivot tables. This function accepts two inputs: a query and a list of column names. The query should produce a result set with two columns: one for row headers and one for data values. The list of column names should correspond to the columns in the result set that should be pivoted.
Question:
Consider the following table named listings
:
id | neighborhood | bedrooms | price |
---|---|---|---|
1 | downtown | 0 | 189000 |
2 | downtown | 3 | 450000 |
3 | riverview | 1 | 300000 |
4 | riverview | 0 | 250000 |
5 | downtown | 1 | 325000 |
6 | riverview | 2 | 350000 |
How to create a pivot table query, with number of bedrooms as columns and neighborhood as rows, showing the average price per bedroom?
The required output should be formatted as follows:
neighborhood | 0 | 1 | 2 | 3 |
---|---|---|---|---|
downtown | 189000 | 325000 | - | 450000 |
riverview | 250000 | 300000 | 350000 | - |
Solution:
To create a pivot table, follow these steps:
-
Calculate the average: Use the
avg()
aggregate function to calculate the average price for each neighborhood and number of bedrooms combination.SELECT neighborhood, bedrooms, avg(price) FROM listings GROUP BY 1, 2 ORDER BY 1, 2;
-
Provide the results to crosstab(): Provide the results of the previous query to the
crosstab()
function. Use$$...$$
to specify an array of values for column names. You can convert the average to an integer to get a rounded result.SELECT * FROM crosstab( 'SELECT neighborhood, bedrooms, avg(price)::int FROM listings GROUP BY 1, 2 ORDER BY 1, 2;', $$SELECT unnest('{0,1,2,3}'::int[])$$ ) AS ct ( "neighborhood" text, "0" int, "1" int, "2" int, "3" int );
This query generates the required pivot table by pivoting on the average price of different bedrooms within each neighborhood.
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