How to Correctly Pass Multiple Data Parameters in an AJAX Call?

AJAX Multiple Data Pass

During the form submission process, it is often necessary to send multiple data fields through AJAX calls. However, passing this data directly can run into problems.

The following code snippet shows an incorrect way of trying to send multiple parameters:

$(document).ready(function() {
  $("#btnSubmit").click(function()  {
    var status = $("#activitymessage").val();
    var name = "Ronny";
    $.ajax({
      type: "POST",
      url: "ajax/activity_save.php",
      **data: "status="+status+"name="+name"**, // 错误的方法
      success: function(msg) {...

In this code, the data parameter is set incorrectly. The correct AJAX data transfer syntax is as follows:

data: {status: status, name: name},

As stated in the jQuery documentation (https://www.php.cn/link/d27bf4d538d65711468835f9daef576e), the data parameter should be an object containing key-value pairs indicating what to send data.

If you still cannot get the expected results, it is recommended to use the alert() function to output the values ​​of the status and name variables respectively to ensure that they contain the correct data as expected.

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