Home >Backend Development >C++ >Can You Determine Design Mode from a Control's Constructor?

Can You Determine Design Mode from a Control's Constructor?

Barbara Streisand
Barbara StreisandOriginal
2025-01-10 12:24:45520browse

Can You Determine Design Mode from a Control's Constructor?

Detecting Design Mode within a Control's Constructor

A prior question raised doubts about determining design mode from within an object's constructor. This article explores a method to achieve this.

Determining Design-Time Status

To identify if a control is in design mode or runtime mode during its construction, leverage the LicenseUsageMode enumeration found in the System.ComponentModel namespace.

Code Example:

<code class="language-csharp">bool isInDesignMode = (LicenseManager.UsageMode == LicenseUsageMode.Designtime);</code>

This concise code snippet uses the LicenseManager.UsageMode property to return a Boolean value. true signifies design mode (visual component manipulation within the IDE), while false indicates runtime mode.

The above is the detailed content of Can You Determine Design Mode from a Control's Constructor?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn