Why Does C# Round Down Integer Division, and How Can I Prevent It?

Understanding Decimal Rounding in C#

When performing divisions in C#, you may encounter instances where the result is rounded down unexpectedly. This behavior stems from integer division, which is the default operation for dividing whole numbers, such as in the example:

double i;
i = 200 / 3;

In this case, the result is 66, even though the actual division result is 66.66666~. To avoid this rounding down, you can employ alternative division techniques.

One approach is to explicitly cast one of the operands to a double, forcing the division to be performed using the double division operator:

i = (double)200 / 3;

Alternatively, you can declare one of the constants as a double:

i = 200.0 / 3;

Or, you can use the suffix d to indicate a double literal:

i = 200d / 3;

By declaring one of the constants as a double, you ensure that the double division operator is utilized, thereby preventing integer rounding and preserving the decimal value.

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