How Can I Create a Dynamically Sized Array in C ?

Variable-Sized Array in C

Initializing an array with a variable length is not allowed in C . However, in certain implementations like G , this practice is allowed as an extension.

int n = 10;
double tenorData[n] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

This code will result in an error because "tenorData" is a variable-sized object that cannot be initialized. To resolve this issue, you can specify the array size as a numeric literal:

double tenorData[10] = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};

Alternative Approaches

If you truly require a dynamically sized array, C provides several options:

• Dynamic Memory Allocation: Manual allocation using new and delete[].

int n = 10;
double* a = new double[n];
// ...
delete[] a;

• Standard Containers: Using standard containers like std::vector.

int n = 10;
std::vector<double> a(n);

Constant-Sized Arrays

If a variable-sized array is not necessary, you can create a fixed-size array using a constant:

const int n = 10;
double a[n];

Or, you can use a constexpr in C 11:

constexpr int n()
{
    return 10;
}

double a[n()];

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