How to Render Partial Views in ASP.NET MVC on Button Click?

Rendering Partial Views on Button Click in ASP.NET MVC

A common scenario in ASP.NET MVC is the need to dynamically load partial views into a specific section of a page, typically in response to a user action such as clicking a button. This technique allows for the modular and flexible display of content without the need for full page refreshes.

Problem Statement

Suppose you have an ASP.NET MVC application with a search form that requires displaying the search results in a separate section of the page. Upon clicking the search button, you want to retrieve search results and render them using a partial view, but not as a replacement for the entire page content.

Solution

To achieve this, you can implement the following steps:

1. Create a Partial View: Define a partial view with the model that will display the search results.
2. Modify the Search Button: Replace the button in the search form with a regular HTML button and assign it an ID.
3. Implement JavaScript: Add a JavaScript event handler to the search button's click event. In this handler, execute an AJAX call using the jQuery load() function.
4. Configure the Controller Method: The controller method handling the search button click should accept the search parameters and return the partial view with the results as its model.

Example Implementation

HTML:

<button></button>

JavaScript:

var url = '@Url.Action("DisplaySearchResults", "Search")';
$('#search').click(function() {
  var searchText = $('#searchInput').val();
  $('#searchResults').load(url, {searchText: searchText});
});

Controller Method:

public ActionResult DisplaySearchResults(string searchText)
{
  var model = // Build the model based on the searchText parameter

  return PartialView("SearchResults", model);
}

This approach allows the partial view to be rendered dynamically within the specified div without reloading the entire page, providing a user-friendly and efficient way to display search results.

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