How to Handle Unix Timestamps in Go
Introduction
Working with timestamps is essential in programming. When dealing with Unix timestamps, you may encounter an "out of range" error when parsing the timestamp using time.Parse. This article will provide a solution to address this issue in Go.
Problem Statement
Attempting to parse a Unix timestamp using the time.Parse function may result in an error due to an incorrect layout. This can be confusing, as the layout appears to be correct according to the Go documentation.
Solution
The time.Parse function is not intended for parsing Unix timestamps. To parse Unix timestamps, you can use the strconv.ParseInt function to convert the string timestamp into an int64 and then create a time.Time value using time.Unix.
Code Example
Here's a corrected code example that demonstrates how to properly parse a Unix timestamp:
package main import ( "fmt" "time" "strconv" ) func main() { timestamp := "1405544146" i, err := strconv.ParseInt(timestamp, 10, 64) if err != nil { panic(err) } tm := time.Unix(i, 0) fmt.Println(tm) }
The strconv.ParseInt function takes the timestamp string, its base (10 in this case), and the bit size (64 to handle large timestamps). It returns an int64 representation of the timestamp.
The time.Unix function takes the int64 value and creates a time.Time value representing the timestamp.
Result
The code above will output the following:
2014-07-16 20:55:46 +0000 UTC
Conclusion
By using strconv.ParseInt and time.Unix instead of time.Parse, you can successfully parse Unix timestamps in Go and avoid the "out of range" error. This approach provides a straightforward and reliable solution for working with timestamps.
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