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How to Implement Efficient Pagination in ASP.NET MVC using LINQ and Default Route Parameters?

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How to Implement Efficient Pagination in ASP.NET MVC using LINQ and Default Route Parameters?

Pagination in ASP.NET MVC using LINQ and Default Route Parameters

Problem:

How to efficiently implement pagination in an ASP.NET MVC application, allowing users to browse through a large list of items divided into multiple pages?

Answer:

Determining Data Source and Default Parameters

First, identify the data source for your list and define your action method with default arguments for pagination. For instance:

public ActionResult Search(string query, int startIndex = 0, int pageSize = 20)
{
    // ...
}

Using LINQ for Pagination

To split the list of items into pages, use LINQ. For skipping a specific number of items (as determined by startIndex) and retrieving the specified page size (pageSize), you can use the following LINQ expressions:

var page = source.Skip(startIndex).Take(pageSize);

Default Route Configuration

Configure default values for startIndex and pageSize in the routes setup:

        routes.MapRoute("Search", "Search/{query}/{startIndex}",
                        new
                        {
                            controller = "Home", action = "Search",
                            startIndex = 0, pageSize = 20
                        });

Action Links for Pagination

Generate action links for navigating to different pages:

<%=Html.ActionLink("next page", "Search", new {
                query, startIndex = startIndex + pageSize, pageSize }) %>

This approach allows you to break up a list into browsable pages using LINQ, default route parameters, and action links. It streamlines the pagination process and enforces consistent formatting and styling across all pages.

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