How Can I Accurately Compare Double Values in Java?

Effectively Comparing Double Values in Java

In Java, comparing two double values using the equality operator (==) can lead to unexpected results due to the inherent precision limitations of floating-point arithmetic. To overcome this, it's crucial to adopt alternative approaches for comparing double values effectively.

Consider the following example:

double a = 1.000001;
double b = 0.000001;

boolean result = (a - b) == 1.0;

Surprisingly, this comparison evaluates to false, even though intuitively it should be true. This is because the subtraction operation (a - b) results in 0.9999999999999999, which is slightly less than 1.0.

To address this issue, a more robust approach is to employ a margin of error, or delta, within which the values can be considered equal. One way to implement this is using Math.abs():

double a = 1.000001;
double b = 0.000001;
double delta = 0.000001;

boolean result = Math.abs(a - b - 1.0) <p>In this case, if the absolute difference between (a - b) and 1.0 is less than or equal to the predefined delta of 0.000001, the comparison will evaluate to true. This approach allows for more accurate comparisons while accounting for potential precision errors.</p>

The above is the detailed content of How Can I Accurately Compare Double Values in Java?. For more information, please follow other related articles on the PHP Chinese website!