How Can I Pass a Variable Number of Arguments to a Python Function?

Passing Variable Number of Arguments to Functions

In Python, it is possible to pass a variable number of arguments to a function, similar to the varargs concept in C/C .

Solution:

Python provides a special syntax *args that can be used as a non-keyword argument. When you use *args in a function definition, you can pass any number of arguments to that function.

def manyArgs(*arg):
  print("I was called with", len(arg), "arguments:", arg)

>>> manyArgs(1)
I was called with 1 arguments: (1,)
>>> manyArgs(1, 2, 3)
I was called with 3 arguments: (1, 2, 3)

As you can see, Python unpacks the arguments into a single tuple with all the arguments.

For Keyword Arguments:

If you need to handle keyword arguments separately, you can accept them as a separate actual argument. For example:

def manyArgsWithKeywords(*args, **kwargs):
  print("Non-keyword arguments:", args)
  print("Keyword arguments:", kwargs)

>>> manyArgsWithKeywords(1, 2, 3, keyword1="value1", keyword2="value2")
Non-keyword arguments: (1, 2, 3)
Keyword arguments: {'keyword1': 'value1', 'keyword2': 'value2'}

Note that keyword arguments must be specified explicitly after the varargs argument in the function definition.

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