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HomeJavajavaTutorialHow Can I Initialize a HashMap in Java Efficiently?

How Can I Initialize a HashMap in Java Efficiently?

Initializing a HashMap Literall

Initializing a Java HashMap with specific key-value pairs in a concise and literal manner has been an elusive feature for developers. However, advancements in Java have paved the way for simplified map creation.

Java 9 and Later: Factory Methods

From Java version 9 onwards, the Map class introduces factory methods that streamline map creation:

  • Map.of: Can create maps with up to 10 elements using a concise syntax:

    Map<string string> test1 = Map.of("a", "b", "c", "d");</string>
  • Map.ofEntries: Creates maps with any number of elements:

    import static java.util.Map.entry;
    
    Map<string string> test2 = Map.ofEntries(
      entry("a", "b"),
      entry("c", "d")
    );</string>

However, it's important to note that these methods result in immutable maps. For mutable maps, you can create a copy using:

mutableMap = new HashMap(Map.of("a", "b"));

Java 8 and Earlier: Anonymous Class or Function

Prior to Java 9, direct literal initialization was not supported. To achieve a similar effect, you can employ the following techniques:

  • Anonymous Class with Initializer: Define an anonymous subclass that initializes the map in its constructor:

    Map<string string> myMap = new HashMap<string string>() {{
      put("a", "b");
      put("c", "d");
    }};</string></string>
  • Function for Initialization: Create a function to generate a map and use it in the initializer:

    Map<string string> myMap = createMap();
    
    private static Map<string> createMap() {
      Map<string> myMap = new HashMap<string>();
      myMap.put("a", "b");
      myMap.put("c", "d");
      return myMap;
    }</string></string></string></string>

The latter approach is cleaner and avoids any potential pitfalls associated with anonymous subclasses.

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