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How Can I Efficiently Chunk a List into Equally-Sized Segments?

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2024-12-25 00:30:16142browse

How Can I Efficiently Chunk a List into Equally-Sized Segments?

Chunking a List into Equal-Sized Segments

Given a list of arbitrary length, how can you efficiently divide it into equally-sized chunks? This common scenario arises in various programming contexts.

Solution 1 (Generator):

A generator function named chunks provides an iterative approach to achieving this task:

def chunks(lst, n):
    """Yield successive n-sized chunks from lst."""
    for i in range(0, len(lst), n):
        yield lst[i:i + n]

For instance, with a list of numbers ranging from 10 to 74 and a chunk size of 10:

import pprint
pprint.pprint(list(chunks(range(10, 75), 10)))
# Output:
[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],
 [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],
 [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],
 [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],
 [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],
 [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],
 [70, 71, 72, 73, 74]]

Solution 2 (List Comprehension):

A concise list comprehension approach is:

[lst[i:i + n] for i in range(0, len(lst), n)]

Note:

While the generator method is more verbose, it's typically preferred in code readability and maintainability. However, the list comprehension provides a convenient one-liner alternative.

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