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Add Sequential Counter Column to Groups in Pandas DataFrame
In the context of data wrangling, there is a common task of adding a sequential counter column to groups within a pandas dataframe. One approach is to use a callback function as you have demonstrated:
def callback(x): x['seq'] = range(1, x.shape[0] + 1) return x
While this method works, it can be cumbersome and involves defining a separate function. A more concise and elegant solution is to utilize the cumcount() method:
df.groupby(['c1', 'c2']).cumcount()
This method computes the cumulative count for each group, effectively assigning a sequential number to each row within a group. For example, consider the following dataframe:
index | c1 | c2 | v1 |
---|---|---|---|
0 | A | X | 3 |
1 | A | X | 5 |
2 | A | Y | 7 |
3 | A | Y | 1 |
4 | B | X | 3 |
5 | B | X | 1 |
6 | B | X | 3 |
7 | B | Y | 1 |
8 | C | X | 7 |
9 | C | Y | 4 |
10 | C | Y | 1 |
11 | C | Y | 6 |
Applying cumcount() to this dataframe, grouped by c1 and c2, would produce:
index | c1 | c2 | v1 | seq |
---|---|---|---|---|
0 | A | X | 3 | 1 |
1 | A | X | 5 | 2 |
2 | A | Y | 7 | 1 |
3 | A | Y | 1 | 2 |
4 | B | X | 3 | 1 |
5 | B | X | 1 | 2 |
6 | B | X | 3 | 3 |
7 | B | Y | 1 | 1 |
8 | C | X | 7 | 1 |
9 | C | Y | 4 | 1 |
10 | C | Y | 1 | 2 |
11 | C | Y | 6 | 3 |
To start the ordering at 1 instead of 0, simply add 1 to the cumcount() result:
df.groupby(['c1', 'c2']).cumcount() + 1
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