


Why Do Nested Python Functions Access Variables at Execution Time, Not Definition Time?
Nested Functions and Local Variable Access
In Python, nested functions can access local variables from their enclosing scope. However, the timing of this access can be counterintuitive.
Consider the following code snippet:
class Cage(object): def __init__(self, animal): self.animal = animal def gotimes(do_the_petting): do_the_petting() def get_petters(): for animal in ['cow', 'dog', 'cat']: cage = Cage(animal) def pet_function(): print "Mary pets the " + cage.animal + "." yield (animal, partial(gotimes, pet_function)) funs = list(get_petters()) for name, f in funs: print name + ":", f()
Instead of getting the expected output where Mary pets each animal, the output shows "Mary pets the cat" for all three animals. This behavior arises because the nested function pet_function looks up the local variable cage at the time of execution, not at the time of definition.
When the function get_petters is called, the local variable cage is assigned to each animal successively within the loop. However, by the end of the function, cage contains the last value ('cat'). When the functions returned by get_petters are called, they all access the same cage variable with the value 'cat'.
To address this issue, one can use different techniques, such as:
-
Using a partial function with a bound cage variable:
from functools import partial def pet_function(cage): print "Mary pets the " + cage.animal + "." yield (animal, partial(gotimes, partial(pet_function, cage=cage)))
-
Creating a new scope for the nested function:
def scoped_cage(cage): def pet_function(): print "Mary pets the " + cage.animal + "." return pet_function yield (animal, partial(gotimes, scoped_cage(cage)))
-
Binding the variable as a default value for a keyword parameter:
def pet_function(cage=cage): print "Mary pets the " + cage.animal + "." yield (animal, partial(gotimes, pet_function))
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