Home >Backend Development >Golang >Why Does Go's `==` Operator Fail to Compare `time.Time` Structs Correctly, and How Can `Time.Equal()` and `Time.In()` Methods Resolve This?
Time Struct Comparison Anomaly
In Go, the == operator for struct comparison evaluates whether all fields match. This principle applies to time.Time, which includes a location field. Consequently, when comparing two time.Time instances with identical date and time but potentially different location pointers, the == operator yields false.
Consider the following example:
import ( "fmt" "time" ) func main() { // Date 2016-04-14, 01:30:30.222 with UTC location t1 := time.Date(2016, 4, 14, 1, 30, 30, 222000000, time.UTC) // Calculate nanoseconds from 1970-01-01 to t1 and construct t2 base := time.Date(1970, 1, 1, 0, 0, 0, 0, t1.Location()) nsFrom1970 := t1.Sub(base).Nanoseconds() t2 := time.Unix(0, nsFrom1970) // Print comparison results fmt.Println("Time t1:", t1) fmt.Println("Time t2:", t2) fmt.Println("t1 == t2:", t1 == t2) fmt.Println("t1.Equal(t2):", t1.Equal(t2)) // Construct a new time t3 with the same values as t1 t3 := time.Date(2016, 4, 14, 1, 30, 30, 222000000, time.UTC) fmt.Println("t1 == t3:", t1 == t3) }
Output:
Time t1: 2016-04-14 01:30:30.222 +0000 UTC Time t2: 2016-04-14 01:30:30.222 +0000 UTC t1 == t2: false t1.Equal(t2): true t1 == t3: true
As evident from the output, t1 == t2 is false despite t1.Equal(t2) returning true. This discrepancy stems from the different location pointers in t1 and t2, as demonstrated by:
fmt.Println("Locations:", t1.Location(), t2.Location()) fmt.Printf("Location pointers: %p %p", t1.Location(), t2.Location())
Output:
Locations: UTC UTC Location pointers: 0x1e2100 0x1e6de0
Different location pointers indicate that these times refer to the same instant, but observed from different locations.
To ensure consistency when comparing times, consider using the Time.In() method to set the same location:
t2 = t2.In(t1.Location()) fmt.Println("t1 == t2:", t1 == t2)
Output:
t1 == t2: true
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