How Can I Sort One List Based on the Values of a Corresponding List?

Sorting a List by Corresponding Values from a Parallel List

In this scenario, you have two lists, X and Y, where each element in Y corresponds to a value associated with the element in X. Your goal is to sort list X based on the values in list Y.

One efficient approach to accomplish this is to use a list comprehension along with the zip() and sorted() functions:

[x for _, x in sorted(zip(Y, X))]

Let's break down this code snippet:

1. zip(Y, X): This creates a list of tuples, where each tuple contains the corresponding elements from lists Y and X.
2. sorted(... , key=lambda pair: pair[0]): This sorts the generated tuple list based on the first element of each tuple (the values from list Y).
3. [x for _, x in ...]: Finally, a list comprehension is used to extract the second elements of each sorted tuple, which gives you the corresponding X values in sorted order.

Example:

X = ["a", "b", "c", "d", "e", "f", "g", "h", "i"]
Y = [ 0,   1,   1,   0,   1,   2,   2,   0,   1 ]

result = [x for _, x in sorted(zip(Y, X))]
print(result)  # ['a', 'd', 'h', 'b', 'c', 'e', 'i', 'f', 'g']

This code will output the sorted list according to the corresponding values in list Y: ["a", "d", "h", "b", "c", "e", "i", "f", "g"].

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