How Can I Efficiently Find Overlapping Matches in a String Using Go?

Overlapping Pattern Matching in Golang: A Simple Solution

While Go's regexp package provides robust capabilities for pattern matching, it natively lacks support for overlapping matches. To address this, a simple and efficient approach utilizing the strings.Index function offers a more suitable solution.

Consider the following code:

input := "...#...#....#.....#..#..#..#......."
idx := []int{}
j := 0
for {
    i := strings.Index(input[j:], "..#..")
    if i == -1 {
        break
    }
    fmt.Println(j)
    idx = append(idx, j+i)
    j += i+1
}
fmt.Println("Indexes:", idx)

In this snippet, the variable input stores the target string. We initialize an empty slice of integers named idx to store the starting indices of the pattern matches within the input string. The j variable keeps track of the current position in the search.

The core of the solution lies in the for loop. We repeatedly call strings.Index to search for the pattern ".#..". The returned value i represents the first occurrence of the pattern starting from index j. If i is not -1, we have found a match and record its starting index (j i) in the idx slice. We then increment j by i 1 to move the search to the character following the match.

The loop continues this process until there are no more matches found. We then obtain the list of starting indices for all overlapping matches of ".#.." in the input string.

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