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How Can I Avoid Unexpected Behavior When Using Go's `interface{}` with `json.Unmarshal`?

Mary-Kate Olsen
Mary-Kate OlsenOriginal
2024-12-21 08:06:121023browse

How Can I Avoid Unexpected Behavior When Using Go's `interface{}` with `json.Unmarshal`?

Golang interface{} Type Misunderstanding

When using the interface{} type as a function parameter, developers often encounter unexpected behavior, especially when interacting with JSON data through json.Unmarshal.

The Issue:

In Go, interface{} is a type that can hold any value and type. However, it's commonly misunderstood as a typeless container. This misunderstanding arises in situations like:

func test(i interface{}) {
    j := []byte(`{ "foo": "bar" }`)
    json.Unmarshal(j, &i)
    fmt.Println(i)
}

func main() {
    test(Test{})
}

Expected Behavior:
This code attempts to unmarshal JSON data into a Test struct. However, it results in an unexpected conversion of the struct to a map[string]interface{} type.

Explanation:

json.Unmarshal cannot unmarshal JSON into a non-pointer value. Since i is an interface{} holding a Test struct, it's passed as an address (&i) to allow modification. However, json.Unmarshal views the interface{} pointer as a pointer to an interface{} value containing the Test struct. Unable to unmarshal into a non-pointer, it defaults to creating a new map[string]interface{} value for the unmarshaled JSON.

The Right Approach:

To resolve this misunderstanding, consider the following scenario:

func test(i *interface{}) {
    j := []byte(`{ "foo": "bar" }`)
    json.Unmarshal(j, i)
    fmt.Println(*i)
}

func main() {
    var i *Test
    test(&i)
}

Explanation:

  • Pass a pointer to the interface{} parameter, effectively wrapping a pointer in an interface{}.
  • Inside the function, dereference the interface{} pointer and pass it directly to json.Unmarshal.
  • Since i holds a pointer to the Test struct, json.Unmarshal correctly unmarshals the JSON data into the struct.

Conclusion:

interface{} is a type that can hold any value, but it's not simply a placeholder for any type. To avoid unexpected behavior, properly handle pointers when using interface{} as function parameters, especially with JSON operations.

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