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You have identified a variable, "FILENAME.jpg," within a debug print_r() statement but are struggling to access it in PHP code.
When working with variables, it's essential to understand that there are compound data types, such as arrays and objects, which can hold multiple values. To access these values, specific syntax is required.
To access the "FILENAME.jpg" variable in your code, you need to build an expression that traverses through the compound data types until you reach it.
Based on the given output, you have the following path:
$variable -> field_image -> handler -> view -> result[0] -> _field_data['nid']['entity'] -> field_image['und'][0]['filename']
Using the syntax for accessing objects and arrays, here's an example expression to obtain the "FILENAME.jpg" variable:
$field_file = $variable->field_image->handler->view->result[0]->_field_data['nid']['entity']->field_image['und'][0]['filename'];
Accessing variables within nested data structures requires careful expression construction. By understanding the rules for accessing objects and arrays, as well as using tools like var_dump() or debugging plugins, you can effectively extract the values you need.
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