Home >Backend Development >C++ >Why Isn't My C Code's '^' Operator Calculating Powers Correctly?

Why Isn't My C Code's '^' Operator Calculating Powers Correctly?

Patricia Arquette
Patricia ArquetteOriginal
2024-12-20 11:18:15275browse

Why Isn't My C Code's

Why is the Power Operator Not Working as Expected?

In the provided C code, an attempt is made to use the "^" operator for performing power operations. However, the output is incorrect because "^" does not serve as the power operator in C/C . Instead, it is defined as the bit-wise XOR operator.

The code intends to calculate the sum of the powers of the entered number "a" from 1 to 4. To achieve this correctly, the pow() function should be utilized, which requires casting one of its arguments to double. The modified code would be:

#include <stdio.h>

void main(void)
{
    int a;
    double result;
    int sum = 0;
    printf("Enter a number: ");
    scanf("%d", &a);
    for( int i = 1; i <= 4; i++ )
    {
        result = (int) pow((double) a,i);
        sum += result;
    }
    printf("%d\n", sum);
}

Additionally, it's worth noting that since C99, the powf() and powl() functions have been introduced to support float and long double arguments, respectively.

The above is the detailed content of Why Isn't My C Code's '^' Operator Calculating Powers Correctly?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn