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Assigning Value Literals to Generic Struct Fields: Troubleshooting IncompatibleAssignment Errors
In Go, generic types can be defined with constraints that restrict the allowed types for their fields. However, when assigning value literals to such fields, certain constraints can trigger an "IncompatibleAssign" error.
Consider the following scenario:
type constraint interface { ~float32 | ~float64 } type foo[T constraint] struct { val T } func (f *foo[float64]) setValToPi() { f.val = 3.14 }
This code compiles without errors because the constraint interface includes both ~float32 and ~float64. However, if we modify the constraint to also include ~int:
type constraint interface { ~float32 | ~float64 | ~int } type foo[T constraint] struct { val T } func (f *foo[float64]) setValToPi() { f.val = 3.14 // IncompatibleAssign: cannot use 3.14 (untyped float constant) as float64 value in assignment }
We encounter an error because the value literal 3.14 (an untyped floating-point constant) cannot be assigned to all possible instances of foo[T], specifically those where T is ~int.
The issue arises because the method declaration:
func (f *foo[float64]) setValToPi() { // ... }
is merely a declaration. It does not instantiate the generic type foo. The identifier float64 within the square brackets is a type parameter name, not a fixed type.
Therefore, within the method, the only known information about the type of val is that it is constrained by constraint. In this case, constraint is the union ~float32 | ~float64 | ~int, meaning the value 3.14 cannot be assigned to the ~int instance of foo[T].
Solution:
To resolve this issue, we have several options:
func (f *foo[T]) setValToPi() { // ... }
This will result in the same error, but with T instead of float64.
func (f *foo[T]) SetValue(val T) { f.val = val }
This accepts a value of the type parameter type, allowing the assignment of value literals like 3.14 to any subtype within the constraint.
type foo struct { val interface{} } func (f *foo) SetPi() { f.val = 3.14 }
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