How to Efficiently Extract a Pixel Array from a Golang Image Object?

Obtaining a Pixel Array from a Golang Image Object

To obtain a pixel array in the form of a byte array, the following approach can be employed.

Firstly, the image library provides the img.At(x, y).RGBA() method to retrieve the RGBA values for a specific pixel at coordinates (x, y) in the image. To obtain the 8-bit representation of these values, each component must be divided by 255.

To facilitate this process, a bi-dimensional array of pixels can be created as follows:

package main

import (
    "fmt"
    "image"
    "image/png"
    "os"
    "io"
    "net/http"
)

func main() {
    // Register the PNG format (can be extended to other formats)
    image.RegisterFormat("png", "png", png.Decode, png.DecodeConfig)

    file, err := os.Open("./image.png")

    if err != nil {
        fmt.Println("Error: File could not be opened")
        os.Exit(1)
    }

    defer file.Close()

    pixels, err := getPixels(file)

    if err != nil {
        fmt.Println("Error: Image could not be decoded")
        os.Exit(1)
    }

    fmt.Println(pixels)
}

func getPixels(file io.Reader) ([][]Pixel, error) {
    img, _, err := image.Decode(file)

    if err != nil {
        return nil, err
    }

    bounds := img.Bounds()
    width, height := bounds.Max.X, bounds.Max.Y

    var pixels [][]Pixel
    for y := 0; y < height; y++ {
        var row []Pixel
        for x := 0; x < width; x++ {
            row = append(row, rgbaToPixel(img.At(x, y).RGBA()))
        }
        pixels = append(pixels, row)
    }

    return pixels, nil
}

func rgbaToPixel(r uint32, g uint32, b uint32, a uint32) Pixel {
    return Pixel{int(r / 255), int(g / 255), int(b / 255), int(a / 255)}
}

type Pixel struct {
    R int
    G int
    B int
    A int
}

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