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HomeBackend DevelopmentPython TutorialHow Can I Efficiently Find and Remove Duplicate Elements from a Python List?

How Can I Efficiently Find and Remove Duplicate Elements from a Python List?

Finding Duplicates in Lists

In Python, finding the duplicates in a list can be achieved in a few ways, depending on the specific requirements.

Using Sets

Sets in Python are unordered collections that automatically eliminate duplicate elements. To remove duplicates from a list and create a new list with the original order, simply use the set(a) expression.

Getting the List of Duplicates

If you need a list of the duplicate elements, you can use a dictionary to count the occurrences of each element in the original list. Elements with counts greater than one are considered duplicates. The following code demonstrates this approach:

a = [1,2,3,2,1,5,6,5,5,5]

import collections
print([item for item, count in collections.Counter(a).items() if count > 1])

# Output: [1, 2, 5]

Using Set Intersection

Another method to find duplicates is to create a set of unique elements from the original list using set(a). Then, you can find the duplicates by intersecting this set with the original list.

Example with Non-Hashable Elements

If the elements in your list are not hashable (e.g., lists or dictionaries), you can use a brute-force approach by iterating over all pairs of elements and comparing them for equality.

Example Code:

a = [[1], [2], [3], [1], [5], [3]]

no_dupes = [x for n, x in enumerate(a) if x not in a[:n]]
print(no_dupes)  # [[1], [2], [3], [5]]

dupes = [x for n, x in enumerate(a) if x in a[:n]]
print(dupes)  # [[1], [3]]

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