How Can I Resolve Ambiguity When Using Overloaded Function Pointers in C ?

Understanding Overloaded Function Pointers

In C , overloaded functions can introduce ambiguity when working with function pointers. This ambiguity occurs because the compiler cannot automatically determine which overload should be invoked when presented with a function pointer declaration. To clarify this designation and specify the intended overload, several methods can be employed.

Solution 1: Using static_cast<>()

One approach is to utilize the static_cast<>() cast operator. This operator allows you to explicitly cast a function pointer to the desired overload signature. For instance, in the code below, the function pointer is cast to the overload that accepts a character argument:

std::for_each(s.begin(), s.end(), static_cast<void (*)(char)>(&f));

Solution 2: Function Pointer Declaration

Alternatively, you can utilize a function pointer declaration to specify the intended overload. The compiler will then infer the appropriate overload based on the declaration. For example:

void (*fpc)(char) = &f;
std::for_each(s.begin(), s.end(), fpc); // Uses the void f(char c); overload

Member Function Consideration

If the overloaded function is a member function, you will need to employ the mem_fun function template from the header. Alternatively, you can directly use the method presented in the provided Dr. Dobb's article.

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