Understanding Slice Capacity Reduction
Go slices are efficient data structures that use an underlying array for storage. They are represented by a combination of length and capacity, where capacity defines the maximum number of elements that the slice can hold.
Slice Capacity Changes
Manipulating a slice can sometimes affect its capacity:
- s = s[:0] and s = s[:4] leave the slice capacity unchanged because they do not modify the underlying pointer to the array.
- s = s[2:] decreases the slice capacity because it changes the pointer to the new slice by dropping the first two elements.
Example
Consider the following Go program:
package main import "fmt" func main() { s := []int{2, 3, 5, 7, 11, 13} printSlice(s) s = s[:0] printSlice(s) s = s[:4] printSlice(s) s = s[2:] printSlice(s) } func printSlice(s []int) { fmt.Printf("len=%d cap=%d %v\n", len(s), cap(s), s) }
Running this program outputs:
len=6 cap=6 [2 3 5 7 11 13] len=0 cap=6 [] len=4 cap=6 [2 3 5 7] len=2 cap=4 [5 7]
Explanation
Initially, the slice has a length of 6 and a capacity of 6. Changing its length to 0 does not modify the pointer, so the capacity remains unchanged. Extending the length to 4 also keeps the capacity the same. However, slicing the slice from the 2nd element onwards (s = s[2:]) changes the pointer, resulting in a new slice with a length of 2 and a capacity of 4.
Data Recovery
s = s[2:] removes the first two elements from the slice. If you need to recover them, you will need to create a new slice that includes them before performing the s = s[2:] operation.
Memory Representation of Slices
Understanding the memory representation of slices is crucial for comprehending why the capacity of s = s[2:] decreases:
- When a slice is created, it points to an underlying array.
- Slicing a slice does not allocate a new array. Instead, it creates a new slice value with a different pointer to the original array.
- Changing the pointer effectively reassigns the slice to point to a different part of the underlying array. This can affect the capacity.
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