How to Correctly Multiply a Duration by an Integer in Go?

Multiplying Duration by Integer in Go

The question arises when attempting to introduce a random delay in a function for testing concurrent goroutines. By introducing the following line, the function is expected to take up to one second to return:

time.Sleep(rand.Int31n(1000) * time.Millisecond)

However, this approach triggers an error, indicating a mismatch between int32 and time.Duration types. The key to resolving this issue lies in converting the int32 to a time.Duration:

time.Sleep(time.Duration(rand.Int31n(1000)) * time.Millisecond)

By converting the int32 value obtained from rand.Int31n(1000) to a time.Duration, the two types can be multiplied, allowing the function to sleep for a random interval of up to one second.

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