Pitfalls of Deleting a Void Pointer
Imagine the following code snippet:
void* my_alloc(size_t size) { return new char[size]; } void my_free(void* ptr) { delete[] ptr; }
Is it safe to delete the void pointer, ptr, in this manner?
Answer:
As per the C Standard, this is a treacherous practice. Section 5.3.5/3 reads as follows:
"In the first alternative (delete object), if the static type of the operand is different from its dynamic type, the static type shall be a base class of the operand's dynamic type and the static type shall have a virtual destructor or the behavior is undefined. In the second alternative (delete array) if the dynamic type of the object to be deleted differs from its static type, the behavior is undefined."
The footnote following this passage further emphasizes:
"This implies that an object cannot be deleted using a pointer of type void* because there are no objects of type void."
Hence, deleting via a void pointer is strictly forbidden as it can result in unpredictable behavior.
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