Home >Backend Development >Python Tutorial >Why Does `int()` Throw a 'ValueError: invalid literal for int() with base 10: ''' Error?

Why Does `int()` Throw a 'ValueError: invalid literal for int() with base 10: ''' Error?

Susan Sarandon
Susan SarandonOriginal
2024-12-16 00:26:13575browse

Why Does `int()` Throw a

Cannot Parse String to Integer: Understanding the 'ValueError: invalid literal for int() with base 10: ''' Error

When attempting to convert a string to an integer menggunakan int(), you may encounter a "ValueError: invalid literal for int() with base 10: ''" error. This error occurs when the provided string cannot be interpreted as a valid integer.

The error message details the string that caused the conversion failure. In the case of an empty string (''), such as in the error you provided, the int() function cannot recognize it as a numerical value.

Another common scenario is attempting to convert a floating-point value directly to an integer. For instance:

To resolve this, first convert the string to a floating-point value using float():

The above is the detailed content of Why Does `int()` Throw a 'ValueError: invalid literal for int() with base 10: ''' Error?. For more information, please follow other related articles on the PHP Chinese website!

Statement:
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn