How Can I Replace All Variables in fmt.Sprintf() with a Single Value?

Replacing All Sprintf Variables with a Single Value

When utilizing fmt.Sprintf() to format strings, it often involves replacing variables with specific values. However, what if you need to substitute all variables with the same value?

fmt.Sprintf() can indeed accommodate this scenario by using explicit argument indices. These indicies specify which argument should be used for formatting instead of the default sequential behavior.

For instance, to replace all variables in the formatted string with "foo":

val := "foo"
s := fmt.Sprintf("%[1]v in %[1]v is %[1]v", val)

In this example, the explicit argument index [1] is used before each format verb, indicating that all variables should be replaced with the first argument, which is "foo". The resulting string becomes:

"foo in foo is foo"

Here's the breakdown of the syntax:

• %[1]v: Replaces variable 1 with "foo"
• %[1]v is %[1]v: This line effectively states "foo in foo is foo"

You can further simplify this by omitting the explicit argument index for the first variable since it defaults to 1:

fmt.Sprintf("%v in %[1]v is %[1]v", "foo")

This approach provides a convenient way to uniformly replace all variables in your formatted string with a single value.

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