How to Display MySQL Database Images in an HTML Image Tag Using PHP?

Retrieving Images from MySQL Database and Displaying in an HTML Image Tag

Question:

In PHP, you've created a MySQL database with a table that includes a BLOB column for storing JPEG images. You've also written a PHP script, catalog.php, to retrieve the image from the database and display it in an HTML image tag. However, you're experiencing issues accessing the $result variable in your catalog.php script.

Answer:

Directly accessing the $result variable in HTML is not possible. To display the image in the HTML tag, you need to create a separate PHP script to fetch the image data from the database and return it as an image.

Updated catalog.php:

<img  src="/static/imghwm/default1.png" data-src="getImage.php?id=1" class="lazy"    style="max-width:90%"  style="max-width:90%" alt="How to Display MySQL Database Images in an HTML Image Tag Using PHP?" >

New PHP Script: getImage.php:

<?php $link = mysqli_connect("localhost", "root", "", "dvddb");
$sql = "SELECT dvdimage FROM dvd WHERE>

How it Works:

• The catalog.php script calls the getImage.php script with the id of the image you want to display.
• getImage.php connects to the database, executes the SQL query to retrieve the image data, and stores it in the $image variable.
• getImage.php sets the Content-type header to "image/jpeg" and echoes the $image variable, which sends the image data to the browser.
• The browser receives the image data and displays it in the HTML image tag specified in catalog.php.

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