How Can I Prevent Ctrl C from Interrupting `exec.Command` in Go?

Preventing Ctrl C from Disrupting exec.Command in Golang

When executing commands using exec.Command, it's crucial to be aware of the potential for Ctrl C interruptions, even if signal.Notify has been utilized to intercept such signals. This issue can be observed in the following example:

package main

import (
    "log"
    "os"
    "os/exec"
    "os/signal"
    "syscall"
)

func sleep() {
    log.Println("Sleep start")
    cmd := exec.Command("sleep", "60")
    cmd.Run()
    log.Println("Sleep stop")
}

func main() {
    var doneChannel = make(chan bool)

    go sleep()

    c := make(chan os.Signal, 1)
    signal.Notify(c, os.Interrupt)
    signal.Notify(c, syscall.SIGTERM)
    go func() {
        <p>Upon pressing Ctrl C while the program is running, the output indicates that the "sleep" command gets interrupted, even though the main program continues to run:</p><pre class="brush:php;toolbar:false">2015/10/16 10:05:50 Sleep start
^C2015/10/16 10:05:52 Receved Ctrl + C
2015/10/16 10:05:52 Sleep stop

The key to resolving this issue lies in recognizing that the shell signals the entire process group when Ctrl C is pressed. This behavior can be prevented by starting the command in its own process group using the Setpgid and Pgid fields in syscall.SysProcAttr:

cmd := exec.Command("sleep", "60")
cmd.SysProcAttr = &syscall.SysProcAttr{
    Setpgid: true,
}

By incorporating this modification, the "sleep" command will no longer be interrupted by Ctrl C, allowing it to continue running independently.

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