How to Efficiently Add the 'Active' Class to ASP.NET MVC's Html.ActionLink for Bootstrap Navigation?

Adding the "Active" Class to Html.ActionLink in ASP.NET MVC

In ASP.NET MVC, adding an "active" class to the bootstrap navbar is essential. However, the common approach of adding it to the element doesn't align with Bootstrap's guidelines.

The Bootstrap Way

Bootstrap requires the "active" class to be applied to the

element, not the element. This ensures that the active class is always visible, regardless of which element is hovered over.

• @Html.ActionLink("Home", "Index", "Home")
• @Html.ActionLink("About", "About", "Home")
• @Html.ActionLink("Contact", "Contact", "Home")

Automatic Class Application

Rather than manually adding the "active" class to each

, you can use ViewContext.RouteData to automatically determine the current page and apply the class accordingly:

• @Html.ActionLink("Home", "Index", "Home")
• @Html.ActionLink("About", "About", "Home")
• @Html.ActionLink("Contact", "Contact", "Home")

A More Elegant Solution (HtmlHelper Extension)

An even more elegant solution is to create an HtmlHelper extension method:

public static string IsSelected(this HtmlHelper html, string controllers = "", string actions = "", string cssClass = "selected")
{
    var viewContext = html.ViewContext;
    var isChildAction = viewContext.Controller.ControllerContext.IsChildAction;

    if (isChildAction)
        viewContext = html.ViewContext.ParentActionViewContext;

    var routeValues = viewContext.RouteData.Values;
    var currentAction = routeValues["action"].ToString();
    var currentController = routeValues["controller"].ToString();

    var acceptedActions = actions.Trim().Split(',').Distinct().ToArray();
    var acceptedControllers = controllers.Trim().Split(',').Distinct().ToArray();

    return (acceptedActions.Contains(currentAction) && acceptedControllers.Contains(currentController)) ? cssClass : "";
}

Usage:

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• List

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