How Can I Properly Stop a Goroutine's Execution After a Timeout in Go?

Stopping Goroutine Execution with Timeouts in Go

When attempting to terminate goroutine execution upon a timeout, it may appear ineffective. This is because Go's concurrency model operates on the principle of fork-join, where initiating a goroutine (fork) doesn't provide immediate control over its execution. Control is only regained at synchronization points, such as channel communication.

In the given example:

go func() {
    time.Sleep(10 * time.Second)
    fmt.Println("test")
    fmt.Println("test1")
    ch <p>The goroutine continues execution despite the timeout set in:</p><pre class="brush:php;toolbar:false">case <p>This is because the timeout pertains to the receiver (reader) of the channel, not the sender. As the channel is buffered, the sender can continue executing without interruption.</p><p>To achieve the desired behavior, synchronization techniques must be employed. For instance, the channel could be closed upon timeout to prevent further communication:</p><pre class="brush:php;toolbar:false">select {
case 

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