Home >Java >javaTutorial >Why Does My DateTimeFormatterBuilder Unit Test Fail, But Runtime Execution Succeed?
DateTimeFormatterBuilder Test Failure
In a Java application, a test case for the DateTimeFormatterBuilder fails when run as a unit test but works correctly when executed at runtime. The issue arises from the following test method:
public void testFormat() throws Exception { final String startDateFormatA = "25-May-2018 11:10"; final String endDateFormatA = "25-May-2018 11:10"; assertEquals("06:00", callDbController.getTimeDifference(startDateFormatA, endDateFormatA)[1]); }
The test attempts to parse a date string using the DateTimeFormatterBuilder and expects a certain result. However, the test fails when executed at test time.
The discrepancy between the behavior at runtime and test time is due to the fact that the DateTimeFormatterBuilder does not specify a locale in its toFormatter() method. This means that the formatter will use the JVM's default locale, which may differ between runtime and test environments. To resolve the issue, the toFormatter() method should explicitly specify a locale, such as Locale.ENGLISH.
DateTimeFormatter DATE_TIME_FORMAT = new DateTimeFormatterBuilder().parseCaseInsensitive().appendPattern("dd-MMM-yyyy HH:mm").toFormatter(Locale.ENGLISH);
By setting the locale, the DateTimeFormatterBuilder ensures that the formatter will parse dates and times consistently across different environments.
The above is the detailed content of Why Does My DateTimeFormatterBuilder Unit Test Fail, But Runtime Execution Succeed?. For more information, please follow other related articles on the PHP Chinese website!