Retrieving a Pixel Array from an Image in Go
Problem:
Extracting a pixel array from an image in the form of a byte array is necessary for passing it to the texImage2D method of gl.Context. The desired pixel array consists of RGBA values arranged in a sequential order from left to right and top to bottom.
Solution:
To obtain the pixel array, the following steps can be taken:
-
Obtain the Image:
Load the image using image.Decode(a) from an io.Reader like os.File or http.Request.Body. -
Getting Individual Pixels:
Use img.At(x, y).RGBA() to retrieve the RGBA values for each pixel. -
Building the Pixel Array:
Construct a two-dimensional array pixels to represent the pixel arrangement. Iterate over each pixel in the image, adding its RGBA values to the corresponding row in pixels. -
Converting to 8-Bit Representation:
Since the RGBA values are 32-bit integers, divide them by 257 to get the 8-bit representation for the texImage2D method.
package main import ( "fmt" "image" "image/png" "os" "io" "net/http" ) func main() { // Register other formats as needed image.RegisterFormat("png", "png", png.Decode, png.DecodeConfig) file, err := os.Open("./image.png") if err != nil { fmt.Println("Error: File could not be opened") os.Exit(1) } defer file.Close() pixels, err := getPixels(file) if err != nil { fmt.Println("Error: Image could not be decoded") os.Exit(1) } fmt.Println(pixels) } func getPixels(file io.Reader) ([][]Pixel, error) { img, _, err := image.Decode(file) if err != nil { return nil, err } bounds := img.Bounds() width, height := bounds.Max.X, bounds.Max.Y var pixels [][]Pixel for y := 0; y <p>By following these steps, you can effectively obtain a pixel array from an image for use with the texImage2D method in Go.</p>
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