


How to Avoid Infinite Loops When Handling InputMismatchException in a try-catch Block?
try/catch with InputMismatchException Infinite Loop Problem
When implementing code that prompts users to provide integer inputs, utilizing a try/catch block is common practice. However, it's essential to handle exceptions correctly to avoid infinite loops.
In the provided example, an exception is caught within a do-while loop. If an InputMismatchException is thrown, the "Error!" message is repeatedly displayed without executing subsequent loop iterations. This occurs because the input buffer remains in an inconsistent state and the error cannot be resolved simply by catching the exception.
To resolve this issue, the following steps are necessary:
- In the catch block, call input.next(); to clear the input buffer, allowing the user to enter valid data in the next iteration.
- Consider using hasNextInt() before reading integers to check if valid input is available, reducing the likelihood of exceptions.
Here's a modified code snippet demonstrating these corrections:
catch (InputMismatchException e) { System.out.println("Error!"); input.next(); // Clear the input buffer }
Additionally, it's advisable to use explicit catch blocks for specific exceptions, such as InputMismatchException, to handle them appropriately.
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