How to Extract a Filename Without the Path in Go?

Obtain Filename without Path in Go

When working with files and paths in Go, it may be necessary to extract only the filename without the preceding directory structure. This can be a common task for various purposes.

To address this, let's explore an approach that involves the 'filepath' package. This approach simplifies the process of manipulating file paths and extracting specific components.

Solution Using filepath.Base:

The 'filepath.Base' function returns the last element of a file path, effectively providing you with just the filename. It essentially removes any leading directory components.

Here's how you can implement this solution:

package main

import "fmt"
import "os"

func main() {
    line := "/some/path/to/remove/file.name"
    file := filepath.Base(line)
    fmt.Println(file) // Prints: file.name
}

By utilizing the 'filepath.Base' function, you can easily obtain the filename while discarding the path information. This provides a concise and efficient solution to your requirement.

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