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HomeBackend DevelopmentC++How to Correctly Initialize Base Class Member Variables in a Derived Class Constructor?

How to Correctly Initialize Base Class Member Variables in a Derived Class Constructor?

How to Initialize Base Class Member Variables in Derived Class Constructor

In object-oriented programming, it's common to have derived classes that inherit from base classes. When creating a constructor in a derived class, it's essential to properly initialize member variables inherited from the base class.

Consider the following code:

class A {
public:
    int a, b;
};

class B : public A {
    B() : A(), a(0), b(0) {
    }
};

In this example, the derived class B attempts to initialize the member variables a and b within its own constructor. However, this is an incorrect approach. The correct way to initialize base class member variables in a derived class is to use the base class's constructor:

class A {
protected:
    A(int a, int b) : a(a), b(b) {} // Accessible to derived classes
private:
    int a, b; // Keep these variables private in A
};

class B : public A {
public:
    B() : A(0, 0) // Calls A's constructor, initializing a and b in A to 0.
    {
    }
};

By making the base class constructor accessible (protected or public) and calling it in the derived class's constructor, we properly initialize the inherited member variables. This approach ensures that the base class is properly initialized before the derived class code executes.

Note that making the base class member variables public in the derived class (as in the incorrect example) is not recommended as it breaks the encapsulation principle, allowing external access to protected or private data.

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